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9x^2+200x-10000=0
a = 9; b = 200; c = -10000;
Δ = b2-4ac
Δ = 2002-4·9·(-10000)
Δ = 400000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{400000}=\sqrt{40000*10}=\sqrt{40000}*\sqrt{10}=200\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-200\sqrt{10}}{2*9}=\frac{-200-200\sqrt{10}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+200\sqrt{10}}{2*9}=\frac{-200+200\sqrt{10}}{18} $
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